Topic: McTest

Anonymous A started this discussion 9 years ago #63,168

McSolve.

Anonymous B joined in and replied with this 9 years ago, 4 minutes later[^] [v] #791,386

McShit

Anonymous C joined in and replied with this 9 years ago, 1 hour later, 1 hour after the original post[^] [v] #791,390

brie !kiTty82duI joined in and replied with this 9 years ago, 10 hours later, 12 hours after the original post[^] [v] #791,421

Insufficient information.

Anonymous E joined in and replied with this 9 years ago, 20 minutes later, 12 hours after the original post[^] [v] #791,424

McInsufficient McInformation

Anonymous A (OP) replied with this 9 years ago, 25 minutes later, 13 hours after the original post[^] [v] #791,429

@791,421 (brie !kiTty82duI)
@previous (E)

McSolve now.

Anonymous E replied with this 9 years ago, 9 minutes later, 13 hours after the original post[^] [v] #791,431

@previous (A)
Mc60

Anonymous F joined in and replied with this 9 years ago, 14 seconds later, 13 hours after the original post[^] [v] #791,432

@791,429 (A)
3x=30
x=10

10+2y=20
2y=10
Y=5

5+2z=9
2z=4
Z=2

X+y+z=?
10+5+2=17

Anonymous E replied with this 9 years ago, 1 minute later, 13 hours after the original post[^] [v] #791,434

@previous (F)
Look again. You fell for it.

Anonymous A (OP) replied with this 9 years ago, 3 minutes later, 13 hours after the original post[^] [v] #791,436

@791,432 (F)
McClose.

Anonymous E replied with this 9 years ago, 1 minute later, 13 hours after the original post[^] [v] #791,437

@previous (A)
The McAnswer is Mc70, no?

(Edited 1 minute later.)

Anonymous A (OP) replied with this 9 years ago, 1 minute later, 13 hours after the original post[^] [v] #791,439

@previous (E)
McIncorrect :(

Anonymous E replied with this 9 years ago, 54 seconds later, 13 hours after the original post[^] [v] #791,441

@previous (A)
It must be 70.

DasSheeple !XPQqN0U9Ew joined in and replied with this 9 years ago, 1 minute later, 13 hours after the original post[^] [v] #791,443

@791,432 (F)
At the end:
5+4z=9
4z=4
z=1 because there are 4 fatty fries packages

Then it's:
y+z*x=?
y+(z*x)=?
5+(1*10)=?
5+10=15

Anonymous E replied with this 9 years ago, 1 minute later, 13 hours after the original post[^] [v] #791,445

The fucking answer is 70. Look at the fucking operation symbols in the last fucking line.

Anonymous A (OP) replied with this 9 years ago, 29 seconds later, 13 hours after the original post[^] [v] #791,446

@791,443 (DasSheeple !XPQqN0U9Ew)
Winner, winner, free McDinner!

Anonymous E replied with this 9 years ago, 8 seconds later, 13 hours after the original post[^] [v] #791,447

Aw shit, the image is too small and I did not see the four fries.

DasSheeple !XPQqN0U9Ew replied with this 9 years ago, 1 minute later, 13 hours after the original post[^] [v] #791,448

@791,445 (E)
Lol, even assuming that fatty fries are 2 and not 1 (because they are double packages in the 3rd line, and single in 4th) your math shills are incredible.

5+2*10=70?

kys

Anonymous F replied with this 9 years ago, 1 hour later, 14 hours after the original post[^] [v] #791,466

@791,447 (E)
Same, was on a phone