Topic: A secret message
The Africa started this discussion 3 weeks ago #132,678
I have encoded a secret message stored between two 56 character long hexadecimal strings. In order to decode the message you must perform some operation for which the following conditions are simultaneously true: a ? b = c, b ? a = c, c ? a = b, a ? c = b, b ? c = a, and c ? b = a. The last two characters of the corrected decoded string are 28.
3c879f10d7380ffb4fa7998ea6270d9ad694611e38a07d083bc82c6a
54f3eb60a40220d436c8ecfad3096ffff9f22b4a5c9550384cab1e52
I want to see if somebody can figure this out.
3c879f10d7380ffb4fa7998ea6270d9ad694611e38a07d083bc82c6a
54f3eb60a40220d436c8ecfad3096ffff9f22b4a5c9550384cab1e52
I want to see if somebody can figure this out.
(Edited 1 minute later.)
Anonymous B joined in and replied with this 3 weeks ago, 1 hour later[^] [v] #1,416,046
Zzzzzz
Anonymous C joined in and replied with this 3 weeks ago, 4 minutes later, 1 hour after the original post[^] [v] #1,416,048
decoder ring joined in and replied with this 3 weeks ago, 1 hour later, 3 hours after the original post[^] [v] #1,416,061
@previous (C)
its a simple substitution cypher with the every digit of the output modified by a highschool teir algebra problem(no doubt of the scholastic level that it existed in before realizing its passion as a semen-powered ottoman and flunking out)
the secret message is thus: "We wuz kangz an sheeitt, now pound my nigussy, crackers."
its a simple substitution cypher with the every digit of the output modified by a highschool teir algebra problem(no doubt of the scholastic level that it existed in before realizing its passion as a semen-powered ottoman and flunking out)
the secret message is thus: "We wuz kangz an sheeitt, now pound my nigussy, crackers."
The Africa joined in and replied with this 3 weeks ago, 5 minutes later, 3 hours after the original post[^] [v] #1,416,064
@previous (decoder ring)
Is it possible for a substitution cypher to produce an output with 23 unique characters when the input only has 16 unique characters?
Is it possible for a substitution cypher to produce an output with 23 unique characters when the input only has 16 unique characters?
Anonymous D replied with this 3 weeks ago, 47 seconds later, 3 hours after the original post[^] [v] #1,416,065
The Africa replied with this 3 weeks ago, 41 seconds later, 3 hours after the original post[^] [v] #1,416,067
@previous (D)
The last two characters are 28… the decoded string is also 28 characters long…
The last two characters are 28… the decoded string is also 28 characters long…
(Edited 51 seconds later.)
The Africa double-posted this 3 weeks ago, 1 minute later, 3 hours after the original post[^] [v] #1,416,070
Hint: 16^2 = 2^8
The Africa joined in and replied with this 3 weeks ago, 1 day later, 1 day after the original post[^] [v] #1,416,256
Nobody has figured it out yet. I’m surprised.
Anonymous D replied with this 2 weeks ago, 21 hours later, 2 days after the original post[^] [v] #1,416,382
Black Online joined in and replied with this 1 week ago, 1 week later, 1 week after the original post[^] [v] #1,418,566
It’s actually perfect key cryptography only I literally included the key with the encrypted string. The encrypted string and the key are equal in length. They’re both hexadecimal encoded byte arrays. The logical operation that satisfies all of those conditions is XOR. Every two characters represents an integer from 0 to 255. So the output encrypted string is 28 characters long since the inputs are each 56 characters.
The first line becomes
3c879f10d7380ffb4fa7998ea6270d9ad694611e38a07d083bc82c6a
60, 135, 159, 16, 215, 56, 15, 251, 79, 167, 153, 142, 166, 39, 13, 154, 214, 148, 97, 30, 56, 160, 125, 8, 59, 200, 44, 106
And the second line becomes
54f3eb60a40220d436c8ecfad3096ffff9f22b4a5c9550384cab1e52
84, 243, 235, 96, 164, 2, 32, 212, 54, 200, 236, 250, 211, 9, 111, 255, 249, 242, 43, 74, 92, 149, 80, 56, 76, 171, 30, 82
You can think of these two lists of numbers as two vectors, you simply have to XOR each element of each vector to get the unencrypted vector.
104, 116, 116, 112, 115, 58, 47, 47, 121, 111, 117, 116, 117, 46, 98, 101, 47, 102, 74, 84, 100, 53, 45, 48, 119, 99, 50, 56
Now, that vector is a UTF-8 encoded string. If you decode it, you get this YouTube URL.
https://youtu.be/fJTd5-0wc28
The last two characters of the YouTube URL are 28.
You’re welcome.
The first line becomes
3c879f10d7380ffb4fa7998ea6270d9ad694611e38a07d083bc82c6a
60, 135, 159, 16, 215, 56, 15, 251, 79, 167, 153, 142, 166, 39, 13, 154, 214, 148, 97, 30, 56, 160, 125, 8, 59, 200, 44, 106
And the second line becomes
54f3eb60a40220d436c8ecfad3096ffff9f22b4a5c9550384cab1e52
84, 243, 235, 96, 164, 2, 32, 212, 54, 200, 236, 250, 211, 9, 111, 255, 249, 242, 43, 74, 92, 149, 80, 56, 76, 171, 30, 82
You can think of these two lists of numbers as two vectors, you simply have to XOR each element of each vector to get the unencrypted vector.
104, 116, 116, 112, 115, 58, 47, 47, 121, 111, 117, 116, 117, 46, 98, 101, 47, 102, 74, 84, 100, 53, 45, 48, 119, 99, 50, 56
Now, that vector is a UTF-8 encoded string. If you decode it, you get this YouTube URL.
https://youtu.be/fJTd5-0wc28
The last two characters of the YouTube URL are 28.
You’re welcome.
Black Online double-posted this 1 week ago, 20 minutes later, 1 week after the original post[^] [v] #1,418,570
@1,416,070 (The Africa)
> Hint: 16^2 = 2^8
The hint is because 2 characters of base 16 provides the same range as 8 characters of base 2, and there are 8 bits in a byte.
> Hint: 16^2 = 2^8
The hint is because 2 characters of base 16 provides the same range as 8 characters of base 2, and there are 8 bits in a byte.
Anonymous H joined in and replied with this 1 week ago, 2 days later, 2 weeks after the original post[^] [v] #1,418,986
BLACK BEAUTYAnonymous H double-posted this 1 week ago, 14 minutes later, 2 weeks after the original post[^] [v] #1,418,987
Anonymous I joined in and replied with this 1 week ago, 27 seconds later, 2 weeks after the original post[^] [v] #1,418,988
Andrew Yang is Nazbol gang